• Were there any statistically significant findings? Explain why your data is/isn't statistically significant.
• Did you have any unusual values? Explain why your data points are/aren't considered unusual.
• What are a few possible reasons your data may/may not have unusual/significant data points?
• this is the data Number of wait times lower than average from ride 1:27

Number of wait times higher than average from ride 1:18

Number of wait times lower than average from ride 2:25

Number of wait times higher than average from ride 2:20

Total lower or higher than average wait times from ride 1:27+18=45

Total lower or higher than average wait times from ride 2: 25+20=45

Total lower than average wait times:52

Total higher than average wait times:38

Grand total:27+18+25+20=90

CONTINGENCY TABLE

	RIDE1 Soaring	RIDE 2 tsmm	TOTAL
LOW	27	25	52
HIGH	18	20	38
TOTAL	45	45	90

Probabilities

• P(Ride 1) = 45 / 90=0.5
• P(Ride 2) = 45/ 90 =0.5
• P(Low) = 52/90 =0.576
• P(High) = 38/ 90=0.423
• P(Ride 1 Low) = 70/ 90=0.778
• P(Ride 1 High) = 65/ 90 =0.722
• P(Ride 2 Low) = 72/ 90=0.8
• P(Ride 2 High) = 63 / 90=0.7
• P(Ride 1 Low) = 27/ 90 =0.3
• P(Ride 1 High) = 18/ 90 =0.2
• P(Ride 2 Low) = 25/ 90 =0.278
• P(Ride 2 High) = 20/ 90 =0.222
• P(Ride 1 | Low) = 27/ 52 =0.519
• P(Ride 1 | High) = 18/ 38 =0.462
• P(Ride 2 | Low) = 25/ 52=0.481
• P(Ride 2 | High) = 20 / 38=0.526
• P(Low | Ride 1) = 27/ 45 =0.6
• P(High | Ride 1) = 18/ 45 =0.4
• P(Low | Ride 2) = 25/ 45=0.556
• P(High | Ride 2) = 20/ 45=0.444

Approximating Binomial Probabilities

Use the table above to determine the probability of the higher-than-average wait times for theride 1sample data set happening by accident. you'll need to find the binomial approximation of the probability that a sample that has 45 wait times will have a probability that falls below the value you got in your contingency table assuming there's a 50% chance of a day not falling in the higher-than-average wait times group (high) for variable 1.

n = ________45____________ p = ____.50______________ q = ______1-.50=.50______________

x = ___________27________ approximated x value = __27.5__________________