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What else would need to be congruent to show that / ABC= _ XYZ by SAS? B y Given: AB = XY A C Y

What else would need to be congruent to show that / ABC= _ XYZ by SAS? B y Given: AB = XY A C Y Z BC = YZ A. ZC= ZZ O B. BC = YZ O C. ZBEZY D. AC = XZ

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