Question
What happens when we write this code snippet? int x = 1; int x = x + 1; x = x + 1; System.out.println(x); Question
What happens when we write this code snippet? int x = 1; int x = x + 1; x = x + 1; System.out.println(x);
Question 2 options:
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It has a compile error because on the third line the type of x is not specified
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It compiles, but has a runtime error when printing x because x has multiple values during the program
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It compiles and runs correctly, and prints 3
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It has a compile error because x cannot be declared twice
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Retake question
What output would be produced by this code snippet? System.out.print(8); System.out.println("cats"); System.out.print(7);
Question 6 options:
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8.0cats 7.0
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8cats7
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8cats 7
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8 cats 7
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