What is the energy released in this ${}^{-}$nuclear reaction ${?}_{34}^{79}Se{?}_{35}^{79}Br+{?}_{-1}^{0}e?($The atomic mass of ${?}^{79}Se$ is $78\mathrm{.}918499u$

and that of ${?}^{79}Br$ is $78\mathrm{.}918337u)$

MeV