Question
What is the equation of the parabola with a directrix at y = -4 and focus (0, 4)? x = -(1/16)y^2 y = -(1/16)x^2 y
What is the equation of the parabola with a directrix at y = -4 and focus (0, 4)?
x = -(1/16)y^2
y = -(1/16)x^2
y = (1/16)x^2
x = (1/16)y^2
Write the equation of a parabola with a vertex at (0, 0) and a focus at (0, -5).
x = -(1/20)y^2
y = -(1/20)x^2
y = (1/20)x^2
x = (1/20)y^2
What is the equation of a parabola with a vertex at (0, 0) and a directrix x = 4?
y = -(1/16)x^2
x = -(1/16)y^2
x = (1/16)y^2
y = (1/16)x^2
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Transportation A Global Supply Chain Perspective
Authors: John J. Coyle, Robert A. Novak, Brian Gibson, Edward J. Bard
8th edition
9781305445352, 1133592961, 130544535X, 978-1133592969
