what is the hypothesis that proportion of times that air quality meets standards is at least 90 percent?

Time Air Quality 0:00:00 0:00:30 1 0:01:00 0 0:01:30 1 0:02:00 1 0:02:30 1 0:03:00 0 0:03:30 1 0:04:00 1 0:04:30 1 0:05:00 1 0:05:30 0 0:06:00 0:06:30 1 0:07:00 1 0:07:30 0:08:00 0:08:30 1 0:09:00 1 0:09:30 0:10:00 1 0:10:30 1 0:11:00 1 0:11:30 0:12:00 1 0:12:30 0:13:000:13:30 O 0:14:00 0 0:14:30 1 0:15:00 0:15:30 1 0:16:00 0:16:30 1 0:17:00 0:17:30 0 0:18:00 0:18:30 0 0:19:00 0:19:30 1 0:20:00 1 0:20:30 1 0:21:00 1 0:21:30 0:22:00 1 0:22:30 1 0:23:00 0 0:23:30The sample proportion is the mean of the Air Quality values. Compute the mean to 4 decimal place accuracy. Test H0: 11 a 0.90. An Air Qualityr instrument logs 0 when standards are not met and 1 when standards are met. The log is saved to file DATA. First, compute the proportion meeting standards as the mean of Air Quality values. Second. at alpha = 0.10 (sensitive. exploratorv}, test the hypothesis that proportion of times that air quality meets standards is at least 90%. O The pvalue of 0.966 indicates that the data provide insignificant evidence against H0: 11 a 0.90. H0 is not rejected at or = 0.10. The status quo remains unchanged. 0 The pvalue of 0.022 indicates that the data provide strong evidence against H0: 11' a 0.90. H0 is rejected at o: = 0.10. The status quo has changed. 0 The pvalue of 0.062 indicates that the data provide weak evidence against H0: 11' a 0.90. H0 is rejected at or = 0.10. O The pvalue of 0.006 indicates that the data provide overwhelming evidence against H0: 11 a 0.90. H0 is rejected at [X = 0.10. Send out an air quality' alert. 0 None of the answers are correct