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What is the output of the following program? 3 go = threading. Semaphore ( 0 ) def one ( ) : global go go .

What is the output of the following program?
3 go = threading. Semaphore(0)
def one():
global go
go.release()
print("One", end="")
def two():
global go
go.acquire()
print("Two", end="")
t1= threading. Thread (target=one)
t2= threading. Thread(target=two)
t2.start()
t1.start()
t1.join()
t2.join()
22 print("Three", end="")
Question options:
Two One Three
Three Two One
One Two Three
It is not possible to predict the output order
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