What is the output of this program (please read it carefully!)? void swap_numbers (int *ra, int rb) { int rtmp tra *ra = rb; rb = r'Imp; } int main() { int a = 1; int b = 2; swap_numbers (&a, b); printf("after swap_value: a = $d AND = $d ", a,b); return(0); 1 A. after swap_value: a = 1 AND b = 1 B. after swap_value: a = 1 AND b = 2 C. after swap_value: a = 2 AND b = 1 D. after swap_value: a = 2 AND b = 2 E. after swap_value: a = 65789843 AND b = 2 (i.e. 65789843 is the address of a) Darat