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What is the primary problem with the statement below? The effect of room temperature on levels of alertness was significant, F(2, 21) = 1.25, p

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What is the primary problem with the statement below? The effect of room temperature on levels of alertness was significant, F(2, 21) = 1.25, p = .075. O the degrees of freedom are not equal O the result was not significant based on the p value O the result was not significant based on the numerator degrees of freedom value O there are no means or standard deviationsTABLE 11-1 An airline wants to select a computer software package for its reservation system. Four software packages (1, 2, 3, and 4) are commercially available. The airline will choose the package that bumps as few passengers as possible during a month. An experiment is set up in which each package is used to make reservations for 5 randomly selected weeks. (A total of 20 weeks was included in the experiment.) The number of passengers bumped each week is obtained, which gives rise to the following Excel output: ANOVA Source of Variation F crit Between Groups 3.238867 Within Groups Total Referring to Table 11-1, the among-group (between-group) mean squares is O 212.4. O 637.2. O 8.525. O 70.8.Solve the problem. A certain HMO is attempting to show the benefits of managed care to an insurance company. The HMO believes that certain types of doctors are more cost-effective than others. One theory is that certification level is an important factor in measuring the cost-effectiveness of physicians. To investigate this, the HMO obtained independent random samples of 21 physicians from each of the three certification levels-Board certified (C); Uncertified, board eligible (E); and Uncertified, board ineligible (1)-and recorded the total per-member, per-month charges for each (a total of 63 physicians). In order to compare the mean charges for the three groups, the data will be subjected to an analysis of variance. Give the degrees of freedom appropriate for conducting the ANOVA F-test. O numerator df = 61, denominator df = 2 O numerator df = 3, denominator df = 60 numerator df = 61, denominator df = 3 numerator df = 2, denominator df = 60Identify the value of the test statistic. Source DF S'S MS F P Factor 3 30 10.00 1.6 0.264 Error 8 50 6.25 Total 11 80 O 30 O 0.264 O 1.6 O 10.00

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