What is the probability of randomly selecting an income greater than X = $75,000 per year in a set of full-time employees? The mean income is M = $50,000 per year and has a standard deviation of SD = $10,000. Calculate the z-score and provide the probability value. Show your work. Use the following formula to obtain the z-score: z = (X - M)/SD a. z = 1.75; p = .0401 b. z = 1.75; p = .9599 C. z= 2.50; p = .0062 d. z= 2.50; p = 9938