What is the standard enthalpy of formation of liquid methylamine (CH3NH2)? 4CH3NH2(1) + 1302(9) 4CO2(g) + 4NO2(g) + 10H2O(1) AH = 4110.4 kJ C(s) + O2(g) + CO2(g) AH = -393.5 kJ 2H2O(l) - 2H2(g) + O2(g) AH = 571.6 kJ 1/2 N2(g) + O2(g) NO2(g) AH = 33.10 kJ; a. -47.3 kJ/mol b. +47.3 kJ/mol O c. +3899.2 kJ/mol O d. +3178.4 kJ/mol e-3899 2 kJ/mol