What is wrong with the following formula if cell C$4$ contains the logical value of TRUE, cell $C1$ contains the text string eligible and cell $C2$ contains the text string ineligible?

$=$IF$($C$4=$"TRUE", C$1,$ C$2)$

since $C2$ equates to the text string "ineligible", the function will return incorrect results

cell C$1$ and C$2$ cannot be referenced in an IF function

since "TRUE" with quotes is a label or text string and not a logical value, it could lead to an incorrect result

nothing ; the formula works as expected with no errors