When 20.0 g C2H6 MM= 30 g/mol) and 60.0 g 02 [MM= 32 g/mol) reacted to form CO2 and H20. 22.5 g of H2O (MM= 18 g/mol) produced, what is the percent yield of H20 in this reaction? (2 Points) 2C2H6 + 702 --> 4CO2 + 6H20 65.5% 86.5% 50.0 % (77.8%