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When learning C programming for the first time, one of the most common mistakes people make is use of pointers in swap function. The classic
When learning C programming for the first time, one of the most common mistakes people make is use of pointers in swap function. The classic example is: /* This is wrong void swap(int a, int b) int temp; temp ai b-temp; b b, /* This is correct* void swap (int *a, int *b) int temp; temp *a *a*b; *b-temp One of the reasons we study computer architecture is to get a deeper understanding of how programs execute on machines. The immediate effect you will see is better understanding of the execution model of C programs. Our goal here is to explain why the first version of the code snippet is incorrect and why second one is correct. Give your explanation however you would like. We recommend translating the code to some type of assembly language format, whether it is MIPS ISA some virtual instruction set (you can come up with simple one yourself as well
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