When only two treatments are involved. ANOVA and the Student's ttest (Chapter 11) result in the same conclusions. Also, for computed test statistics, (2 = F. To demonstrate this relationship, use the following example. Fourteen randomly selected students enrolled in a history course were divided into two groups, one consisting of six students who took the course in the normal lecture format. The other group of eight students took the course in a distance format. At the end of the course, each group was examined with a 50-item test. The following is a list of the number correct for each ofthe two groups. Traditional Lecture Distance 33 45 38 35 4O 44 32 3D 31 41 36 31 41 4E Ljpicture Click here for the Excel Data File. Required: a-1. Complete the ANOVA table. (Round your 55, MS, and Fvalues to 2 decimal places and p-value, Fcrit to 4 decimal places.) Sou roe of Va riatio n Treatment Error a-2. Use a c: = 0.05 level of signicance, compute the critical value. (Round your answer to 2 decimal places.) [The critical value of F is b. Using the ttest from Chapter 11, compute t (Negative amount should be indicated by a minus sign. Round your answer to 3 decimal places.)