When using substitution to evaluate ${\displaystyle \underset{\phantom{}}{\overset{\phantom{}}{}}}18x(3x^2+5{)}^{9}dx$ which integral is the correct one to use for $u-$substitution?

${\displaystyle \underset{\phantom{}}{\overset{\phantom{}}{}}}\frac{1}{3}{u}^{9}du$

${\displaystyle \underset{\phantom{}}{\overset{\phantom{}}{}}}{u}^{9}du$

No answer text provided.

${\displaystyle \underset{\phantom{}}{\overset{\phantom{}}{}}}3u^{9}du$

${\displaystyle \underset{\phantom{}}{\overset{\phantom{}}{}}}18x{u}^{9}du$