where $k\frac{T}{q}$~~$26$meV at room temperature, and $I_S=8\mathrm{.}58{10}^{-8}mA.$

a$)$ Under AM$1\mathrm{.}5$G conditions, $I_{SC}$ was found to be $26mA.$ Estimate $V_{OC}.$

b$)$ Out of curiosity, the engineer took the cell into a well$-$illuminated lab indoor. There, he

used an optical power meter and discovered that the total incident power is about $1000$

times less than the AM$1\mathrm{.}5$G conditions. He discovered the cell gives an overall $I_{SC}$ of about

$30A.$ Will he be able to measure $V_{OC}?$ If yes, what should be $V_{OC}?$ If not, explain why

he cannot measure now.An engineer attempted to evaluate the performance of a small Si pn junction solar cell. The

relationship between the short circuit current $(I_{SC})$ and the open$-$circuit voltage $(V_{OC})$ of the cell

can be described very well by the equation:

$V_{oc}$~~$\frac{kT}{q}ln(\frac{I_{SC}}{I_S})$

where $k\frac{T}{q}$~~$26$meV at room temperature, and $I_S=8\mathrm{.}58{10}^{-8}mA.$

a$)$ Under AM$1\mathrm{.}5$G conditions, $I_{SC}$ was found to be $26mA.$ Estimate $V_{OC}.$

b$)$ Out of curiosity, the engineer took the cell into a well$-$illuminated lab indoor. There, he

used an optical power meter and discovered that the total incident power is about $1000$

times less than the AM$1\mathrm{.}5$G conditions. He discovered the cell gives an overall $I_{SC}$ of about

$30A.$ Will he be able to measure $V_{OC}?$ If yes, what should be $V_{OC}?$ If not, explain why

he cannot measure now.