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What would the pOH value of $0\mathrm{.}050M$ solution of acetic acid be at room temperature? $($acetic acid $($:$=C{H}_3\frac{C}{O}OH\}$

$0\mathrm{.}050MC{H}_3\frac{C}{O}OH$

$C{H}_3\frac{C}{O}OH>()-$

$)-$

At $25$ degrees celsius, acetic acid's $Ka=1\mathrm{.}74{10}^{-5}$