Which of the following pairs has the same number of atoms?

$($i$)16g$ of $O_2(g)$ and $4g$ of $H_2(g)$

$($ii$)16g$ of $O_2$ and $44g$ of $C{O}_2$

$($iii$)28g$ of $N_2$ and $32g$ of $O_2$

$($iv$)12g$ of $C(s)$ and $22g$ of $Na(s)$

One mole of any substance contains $6\mathrm{.}022{10}^{23}$ atoms$/$molecules$.$ Number of $m$ of $H_{2}S{O}_4$ present in $100mL$ of $0\mathrm{.}02M{H}_{2}S{O}_4$ solution is

$($i$)12\mathrm{.}044{10}^{20}$ molecules

$($ii$)6\mathrm{.}022{10}^{23}$ molecules

$($iii$)1{10}^{23}$ molecules

$($iv$)12\mathrm{.}044{10}^{23}$ molecules