Worksheet # 3 Universal Gravity a mi savory p4 0.006 to seam a rillw olilloise A . Of x 80.8 el wthe 1 end to east .coshue e'rthe3 F = GM m F = force of gravity G = gravitational constant (6.67 x 10-1) HOW LIA WOHE M = mass of one object m = mass of other object r = distance between the 50 cm I'm two objects 12 10.5m 100 (m 1. A 50.0 kg person and a 75.0 kg person are sitting on a bench approximately 50.0 cm beoslq apart. Estimate the magnitude of the gravitational force each exerts on the other. Show insilu all work, include equation and substitutions. F - C, 67x 10 (50 kg) (75kg) mort balsloei bejdo erll no sotot ism (0 , 5) 2 F zeisvinu ertl to 2. What is the force of gravity acting on a 2000. kg spacecraft when it orbits two Earth radii from the center of the Earth. ( Earth has a radius of 6380 km) The mass of the Earth is 5.98 x 10 24 kg OLX POLL 3. Find the net force on the Earth due to the gravitational attraction to both the Moon and the sun assuming that they are at a right angle to each other. [ The mass of the moon is 7.35 x 10 22 kg, the mass of the Earth is 5.98 x 10 24 kg, mass of the sun is 1.99 x 1030 kg, Average distance from the Moon to the Earth is 384 x 10 3 km, average distance to the sun is 149.6 x 10 6 km. Show all work! moon of the Moon Moon gravitations as of the sun E Sun X HO Earth "OLX 80.15 8574. A satellite with a mass of 300.0 kg moves in a circular orbit 5.00 x 10 7 m above the Earth's surface. Mass of the Earth is 5.98 x 10 24 kg, Radius of the Earth is 6380 km MO SHOW ALL WORK! A] What is the gravitational force on the satellite? B] What is the speed of the satellite? C] What is the period of the satellite? mo 0.02 VI s no politie 5. Three uniform spheres of masses m, = 3.50 kg, m2 = 4.0 kg and my = 6.50 kg are placed at the corners of a right triangle as shown in the diagram below. Calculate the resultant gravitational force on the object of mass m2, assuming that the spheres are isolated from the rest of the universe. nosobga 3 (0, 3.00) ml FB = d ( F . 2 ) 2 + ( F 32) 21 10AW orit mont my FR = 7 (104 x 10- 10 )2 + (1 08 x 10 -10) 2 (-4.00, 0) m F12 FR = 1. 50 X 10-10 x Jen om bain Fg2 OT mz Herito ross of ale art! erll of sunsleib opsrevs , ml Or x ABS elkins ] arti of nooM erit mon) so F12 = Fg = G mimz 2 = 6.67 x 10-1 s world_ 1 (3 . 50 kg ) ( 4.0kg) ( 3.0 m ) ? F12 = 1. 04 x 10- 10 F23 = Fg 23 = 6 mimz 1 2 = 6 : 67 + 10 - (4. 00 ka (6.50) ( 4. 0m ) 2 F23 = 1.08 x 10 - 10