Write a function named equivalentArrays that has two array arguments and returns $1$ if the two arrays contain the same values $($but not necessarily in the same order$),$ otherwise it returns $0.$ Your solution must not sort either array or a copy of either array! Also you must not modify either array, i$.$e$.,$ the values in the arrays upon return from the function must be the same as when the function was called. Note that the arrays do not have to have the same number of elements, they just have to have one of more copies of the same values.

If you are programming in Java, the function prototype is int equivalentArrays$($int$[]$ a$1,$ int$[]$ a$2)$

Hint: If your solution compares the length of the first array with the length of the second array or vice versa, you have misunderstood the problem!! Your solution does not need to determine which array is bigger!

Examples:

if a$1$ is and a$2$ is return

$\{0,1,2\}\{2,0,1\}1($because both arrays contain the values $0,1,2)$

$\{0,1,2,1\}\{2,0,1\}1($because both arrays contain the values $0,1,2)$

$\{2,0,1\}\{0,1,2,1\}1($because both arrays contain the values $0,1,2)$

$\{0,5,5,5,1,2,1\}\{5,2,0,1\}1($because both arrays contain the values $0,1,2,5)$

$\{5,2,0,1\}\{0,5,5,5,1,2,1\}1($because both arrays contain the values $0,1,2,5)$

$\{0,2,1,2\}\{3,1,2,0\}0($the value $3$ is not in the first array$)$

$\{3,1,2,0\}\{0,2,1,0\}0($the value $3$ is not in the second array$)$

$\{1,1,1,1,1,1\}\{1,1,1,1,1,2\}0($the value $2$ is not in the first array$)$

$\{\}\{3,1,1,1,1,2\}0(3$ is not in the first array.$)$

$\{\}\{\}1($not possible to find a counterexample$)$