Write a method digitCount(int number, int digit) which takes an integer (it could be negative) and a digit (between 0 and 9), and returns the number of times the given digit occurs in the given integer. You may not convert the numbers to strings here. Solve this problem numerically.

digitCount(456234, 8) returns 0

digitCount(456234, 5) returns 1

digitCount(456234, 4) returns 2

digitCount(-456234, 4) returns 2

digitCount(0, 0) returns 1