Write an 8086 assembly program using the windows32 or windows64 framework, write a program that will find the sum of even numbers from 20 to 0 then display the result with appropriate message to the user.

***(Add comments and keep the code very well organized)*** Have nothing, need help with whole thing. Please help!

Would like you to write the code out organized similar to the code added to the bottom of the question.

Also need to have an image of the ouput to show that it actually worked and isnt just random code written out.

.586

.MODEL FLAT

INCLUDE io.h

.STACK 4096

.DATA

prompt BYTE "Enter a number:", 0

string BYTE 40 DUP (?)

resultLbl BYTE "Your number is:", 0

positiveLbl BYTE "Positive", 0

negativeLbl BYTE "Negative", 0

.CODE

_MainProc PROC

mov ecx, 10 ; the for loop will run 10 times (change to a lower # for testing purposes)

forCount: input prompt, string, 40 ; prompt user for a number

atod string ; convert to integer

cdq ; extend the sign of EAX to EDX (getting ready to divide EDX:EAX)

mov ebx, 2

idiv ebx ; divide by 2 and check the remainder (stored in EDX) to see if the number is odd or even

cmp edx, 0 ; compare the remainder with 0

jne negative ; if the remainder is not 0, the number is odd

; else the number has to be even

positive: output resultLbl, positiveLbl ; output the even message

jmp exit

negative: output resultLbl, negativeLbl ; output the odd message

jmp exit

exit:

loop forCount ; go to the next iteration of the for loop

_MainProc ENDP

END