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Write an answer in Golang - - The answer you have provided is wrong. All the examples result in 2 - 2 - 2 instead

Write an answer in Golang -- The answer you have provided is wrong. All the examples result in 2-2-2 instead of 4-3-5
There is an array A made of N integers. Your task is to choose as many integers from A as possible so that, when they are put in ascending order, all of the differences between all pairs of consecutive integers are equal. For example, for A =[4,3,5,1,4,4], you could choose 1,3, and 5(with differences equal to 2) or 4,4, and 4(with differences equal to 0). So, answer in this case will be 3.
What is the maximum number of integers that can be chosen? Write a function.
Example 1 :
A =[4,7,1,5,3], function should return 4.4 integers (7,1,5,3) when put in ascending order the difference between all consecutive integers is 2.
Example 2 :
A =[12,12,12,15,10], function should return 3. It is optimal to chose all 3 integers with value 12.
Example 3 :
A =[18,26,18,24,24,20,22], function should return 5.5 integers (18,20,22,24,26) when put in ascending order the difference between all consecutive integers is 2. Notice that we cannot pick any other integers, even though they occur more than once.
Your answer follows here ---
package main
import (
"fmt"
"sort"
)
// Function to find the maximum number of integers with equal differences
func maxIntegersWithEqualDifferences(arr []int) int {
// Sorting the array
sort.Ints(arr)
// Initialize variables
maxCount :=0// Variable to store the maximum count of integers with equal differences
n := len(arr)// Length of the input array
// Loop through the array
for i :=0; i < n; i++{
count :=1// Initialize the count of consecutive integers with equal differences to 1
for j := i +1; j < n; j++{
// Check if the difference between current and next element is equal to the difference between the first two elements
if arr[j]-arr[j-1]== arr[1]-arr[0]{
count++// Increment count if the difference is equal
} else {
break // Break the loop if the difference is not equal
}
}
// Update maxCount if the current count is greater
if count > maxCount {
maxCount = count
}
}
return maxCount // Return the maximum count of consecutive integers with equal differences
}
func main(){
// Example arrays
arr1 :=[]int{4,7,1,5,3}
arr2 :=[]int{12,12,12,15,10}
arr3 :=[]int{18,26,18,24,24,20,22}
// Function calls and output
fmt.Println("Example 1:", maxIntegersWithEqualDifferences(arr1))// Output: 4
fmt.Println("Example 2:", maxIntegersWithEqualDifferences(arr2))// Output: 3
fmt.Println("Example 3:", maxIntegersWithEqualDifferences(arr3))// Output: 5
}
The answer that you keep on giving me is wrong. If you run the above go code the output would be 2-2-2 instead of 4-3-5. Try it out , and you will see that your answer is incorrect.

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