Write C code for the following 1. (Birthday paradox revisited) Compute analytically the probability that at least two people in a group of N persons have the same birthday. Hint: Let's say, N 4. Then, the number of possible birthday combinations for 4 persons is 365 x365 x365 x365. The number of possible cases where 4 persons have different birthdays (no one shares the same birthday) is 365 364 x363 x362. Therefore, the probability that all 4 persons have different birthdays is 365 364 363 362 365 365 365 365 and the probability that at least two people out of4 have a same birthday is 365 364 363 362 - _ = 0.016 1365 365 365 365 Generalize this for N persons and compare the result with the Monte Carlo method