The circuit (Figure 1) for practical 1 is a single BJT common emitter amplifier. Given the following set of requirements, we would calculate and choose the suitable component values: Supply voltages +12 V: Vcc= 12 V, VEE = -12 V Minimum input impedance: Rin = 5 kn Maximum output impedance: Rout = 1 kN Voltage gain: A = -8 E12 preferred values for all components Assume that these equations have been given (you can derive them using the small signal analysis later in the semester): (1) A R3 R4 (2) (3) where r = Rout R3 Rin ~ ( + (B + 1)R4) || R1 || R B BVT B = 125, VT = 25 mV. Im Ic = Us C R R2 www ww R3 VB RA R5 Vc VE ww C Figure 1 Single BJT common emitter amplifier Vcc Vo VEE R5 is (E12 value) Type your answer... O points Step 4: Find R and R2 Consider replacing R and R with its Thevenin's equivalent circuit and then use Equation (3) to find the minimum value of Rth Assume VBE = 0.7 V. Hint: start by calculating VB and IB and then find the equations for Vth and Rth VB is_V = R || R.