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Write recurrence relation of below pseudocode that calculates x ^ n power 2 ( x , n ) : if n = = 0 :

Write recurrence relation of below pseudocode that calculates x^n
power2(x,n):
if n==0:
return 1
if n==1:
return x
if (n%2)==0:
return power2(x, n//2)* power2(x,n//2)
else:
return power2(x, n//2)* power2(x,n//2)* x

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