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Write the justification of the results of the problem. The following graph describes the productive behavior of a ZARA brand clothing factory. Considering that their

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Write the justification of the results of the problem.

The following graph describes the productive behavior of a ZARA brand clothing factory. Considering that their demand is biweekly and equal to the inventory of raw materials that they ask to calculate: Daily demand: [pieces/day] Takt time "real" (of manufactured parts) Total cycle time [sec] [seconds /piece] Time without added value [days] Monthly forecast ZARA Monthly forecast Biweekly order Supplier Biweekly Order Customer/ Store Biweekly Cotton Production Supervision Polyester Zipper Weekly Weekly Weekly Weekly Weekly Weekly Biweekly Cutting Sewing Deburring Inspecting Packaging Shipment X A -9 A 3000 5000 3000 3000 O O 3000 2500 5 40 10 10 10 C/T = 15 secs C/O 60 minutes C/T = 210 secs C/O= 2 hours C/T = 40 secs C/O = 10 minutes C/T = 40 secs C/O 10 minutes C/T = 40 secs C/O= 10 minutes Uptime - 100% 1 shift 27.500 sec avail Uptime = 100% 1 shift 27,500 sec. avail Uptime = 100% 1 shift 27.500 sec, avail Uptime = 100% 1 shift 27.500 sec avail Uptime = 100% 1 shift 27.500 sec, avail Production Lead Time = 15 days 2 days 8 days 3 days O days O days 2 days Process time 345 seconds 15 secs 210 secs 40 secs 40 secs 40 secs Biweekly The following graph describes the productive behavior of a ZARA brand clothing factory. Considering that their demand is biweekly and equal to the inventory of raw materials that they ask to calculate: Daily demand: [pieces/day] Takt time "real" (of manufactured parts) Total cycle time [sec] [seconds /piece] Time without added value [days] Monthly forecast ZARA Monthly forecast Biweekly order Supplier Biweekly Order Customer/ Store Biweekly Cotton Production Supervision Polyester Zipper Weekly Weekly Weekly Weekly Weekly Weekly Biweekly Cutting Sewing Deburring Inspecting Packaging Shipment X A -9 A 3000 5000 3000 3000 O O 3000 2500 5 40 10 10 10 C/T = 15 secs C/O 60 minutes C/T = 210 secs C/O= 2 hours C/T = 40 secs C/O = 10 minutes C/T = 40 secs C/O 10 minutes C/T = 40 secs C/O= 10 minutes Uptime - 100% 1 shift 27.500 sec avail Uptime = 100% 1 shift 27,500 sec. avail Uptime = 100% 1 shift 27.500 sec, avail Uptime = 100% 1 shift 27.500 sec avail Uptime = 100% 1 shift 27.500 sec, avail Production Lead Time = 15 days 2 days 8 days 3 days O days O days 2 days Process time 345 seconds 15 secs 210 secs 40 secs 40 secs 40 secs Biweekly

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