Write the left side of the equation $5sin2x+12cos2x=0$ in the form a $sin(bx-c),$ then solve for $x$ in the interval $[0,2).$ Write the left side of the equation $5sin2x+12cos2x=0$ in the form a $sin(bx-c).$ Choose the correct answer below. A$.5sin[12x+ta{n}^{-1}(\frac{5}{12})]$ B$.$ C$.12sin[5x-ta{n}^{-1}(\frac{5}{12})]$ D$.13sin[2x-ta{n}^{-1}(\frac{12}{5})]$ The solution set for $x$ in the interval $[0,2)$ is $.($Simplify your answers. Type your answers in radians. Do not round until the final answer. Then round to three decimal places a