Answered step by step
Verified Expert Solution
Question
1 Approved Answer
Write valid C++ code to modify the class BinaryHeap (pasted below) to support the following operations: a) decreaseKey(p, d) - Lowers the value of the
Write valid C++ code to modify the class BinaryHeap (pasted below) to support the following operations: a) decreaseKey(p, d) - Lowers the value of the item at position p by a positive amount d. b) increaseKey(p, d) - Increases the value of the item at position p by a positive amount d. c) remove(p) - Removes the node at position p. Also write code to test your routines above.
***********BinaryHeap.H**********************
#ifndef BINARY_HEAP_H #define BINARY_HEAP_H #include "dsexceptions.h" #includeusing namespace std; // BinaryHeap class // // CONSTRUCTION: with an optional capacity (that defaults to 100) // // ******************PUBLIC OPERATIONS********************* // void insert( x ) --> Insert x // deleteMin( minItem ) --> Remove (and optionally return) smallest item // Comparable findMin( ) --> Return smallest item // bool isEmpty( ) --> Return true if empty; else false // void makeEmpty( ) --> Remove all items // ******************ERRORS******************************** // Throws UnderflowException as warranted template class BinaryHeap { public: explicit BinaryHeap( int capacity = 100 ) : array( capacity + 1 ), currentSize{ 0 } { } explicit BinaryHeap( const vector & items ) : array( items.size( ) + 10 ), currentSize{ items.size( ) } { for( int i = 0; i < items.size( ); ++i ) array[ i + 1 ] = items[ i ]; buildHeap( ); } bool isEmpty( ) const { return currentSize == 0; } /** * Find the smallest item in the priority queue. * Return the smallest item, or throw Underflow if empty. */ const Comparable & findMin( ) const { if( isEmpty( ) ) throw UnderflowException{ }; return array[ 1 ]; } /** * Insert item x, allowing duplicates. */ void insert( const Comparable & x ) { if( currentSize == array.size( ) - 1 ) array.resize( array.size( ) * 2 ); // Percolate up int hole = ++currentSize; Comparable copy = x; array[ 0 ] = std::move( copy ); for( ; x < array[ hole / 2 ]; hole /= 2 ) array[ hole ] = std::move( array[ hole / 2 ] ); array[ hole ] = std::move( array[ 0 ] ); } /** * Insert item x, allowing duplicates. */ void insert( Comparable && x ) { if( currentSize == array.size( ) - 1 ) array.resize( array.size( ) * 2 ); // Percolate up int hole = ++currentSize; for( ; hole > 1 && x < array[ hole / 2 ]; hole /= 2 ) array[ hole ] = std::move( array[ hole / 2 ] ); array[ hole ] = std::move( x ); } /** * Remove the minimum item. * Throws UnderflowException if empty. */ void deleteMin( ) { if( isEmpty( ) ) throw UnderflowException{ }; array[ 1 ] = std::move( array[ currentSize-- ] ); percolateDown( 1 ); } /** * Remove the minimum item and place it in minItem. * Throws Underflow if empty. */ void deleteMin( Comparable & minItem ) { if( isEmpty( ) ) throw UnderflowException{ }; minItem = std::move( array[ 1 ] ); array[ 1 ] = std::move( array[ currentSize-- ] ); percolateDown( 1 ); } void makeEmpty( ) { currentSize = 0; } private: int currentSize; // Number of elements in heap vector array; // The heap array /** * Establish heap order property from an arbitrary * arrangement of items. Runs in linear time. */ void buildHeap( ) { for( int i = currentSize / 2; i > 0; --i ) percolateDown( i ); } /** * Internal method to percolate down in the heap. * hole is the index at which the percolate begins. */ void percolateDown( int hole ) { int child; Comparable tmp = std::move( array[ hole ] ); for( ; hole * 2 <= currentSize; hole = child ) { child = hole * 2; if( child != currentSize && array[ child + 1 ] < array[ child ] ) ++child; if( array[ child ] < tmp ) array[ hole ] = std::move( array[ child ] ); else break; } array[ hole ] = std::move( tmp ); } }; #endif
Step by Step Solution
There are 3 Steps involved in it
Step: 1
Get Instant Access to Expert-Tailored Solutions
See step-by-step solutions with expert insights and AI powered tools for academic success
Step: 2
Step: 3
Ace Your Homework with AI
Get the answers you need in no time with our AI-driven, step-by-step assistance
Get Started