Written response section. Indicate your answer in the space provided on this sheet. The Kroll Process makes titanium by the reaction below. TiCl4(s) + 2 Mg(s) - Ti(s) + 2 MgClz(s) N Using the information below, calculate the enthalpy change for the reaction above. (2 marks) Mg(s) + Clz(9) - MgClz(s) AH=-641 kJ 2 Ti(s) + 3 Clz(g) - 2 TiCl3(s) AH=-1448 kJ 2 TiCl3(s) + Clz(9) - 2 TiCl4(s) AH=-192 kJ