X 0 1 2 Six Children Let x represent the number of girls a couple has when having six children. The following table illustrates the probability distribution associated with having girls. 2)P(x21) = P(1) + P(2).... P(6) =0.94 +0.234+0.713+0.234+0.044+0.016 = 0.985 3)P(x 3) = P(4)+P(5) + P(6) 4 0.234 =0,936 x = 0.234 +0.044+0.016 -0.344 5 X 0.094 = 0.47 6 0.016 1.001 = 0.096 3.003 + If you select a person at random, what's the probability the person has: Approximate your answer to the nearest thousandths. = 1. One girl? PC) 0.09 2. At least one girl? P(xz1)=0.99 3. Less than two girls? x 2 = 0.11 4. More than three girls? x>3=0.34 5. No more than two girls? x2 = 0.84 6. Between two and four girls? 2x4 = 0.78 7. What is the mean for this distribution? 5) P(x-2)= P(2) + P(3) + ....P(C) = 0.891 6) P(22x4) = P(2)+P(3) + P(4) 3.00 8 What is the standard deviation for this distribution? (.41 = 0.781 8) 3.003 -1.001 = 1.41