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x=317 n=350 Success rate(p) = x/n = 0.9057 = 0.1 Z/2 = 1.282 Null Hypothesis = Ho: p = 0.90 Alternative Hypothesis = H1 :

x=317

n=350

Success rate(p) = x/n = 0.9057

= 0.1

Z/2 = 1.282

Null Hypothesis = Ho: p = 0.90

Alternative Hypothesis = H1 : p > 0.90

z =p - p /(square root (p (1-p))/n)

= (317/350) - 0.90/ square root((0.90)(1-0.90))/350

= 0.0057142857 / 0.0160356727

=0.3563471553 = 0.3563

Zo = 0.3563

Critical Value

Z/2 = 1.282

|zo | < | z alpha |

p-value: right tail -Ha : ( p > 0.35635 ) = 0.36079

p= x/n317/350 =0.9057142857

Ho : 0.3563

H1: 0.36079

There are 317 (2s) and 33 (1s)

QUESTION :

Based on your sample proportion, what is the probability of randomly choosing 3 of the 350 participants and finding all 3 that would not purchase another lexus ?(calculations)

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