(x+5)2 _ (y+2)2 = 1 Rupert graphs the hyperbola 64 36 How does he proceed? Drag a value, phrase, equation, or coordinates in the boxes to correctly complete the statements. J Rupert first identifies the center of the hyperbola as ! and that the hyperbola opens L - Since a = the coordinates of the vertices are 7 The slopes of the asymptotes of this parabola are and the asymptotes pass through the center of the hyperbola. The equations of the asymptotes are Once this information is gathered, the asymptotes are graphed as dashed lines, and the hyperbola is drawn through the vertices, approaching the asymptotes.\f