XII. The likelihood that the new initiative will generate them the $5,000,000 in income that they have estimated based on significance level of 0.05 S N S=4,950,000 x 15% = 742,500 T = $4,950,000 - $5,000,000742,500/square root of 5) = ???? The critical value is 2.132 and comparing t to the critical value, the null hypothesis cannot be rejected, and the project can be undertaken to generate the desired revenue