Yes or No? 1. f(x)=/x] can Not be integrable over [-1, 1] because it is not differentiable at x=0. 2. [ f(x)dx=lim _ f(c,)Ax; ) will always be true for any function f, when [a, b] is partitioned into {x1, x1, ..., ), with Ax; = x; -X1: and c, is in [x x1]_ 3. By definition, | f(x)dx = -[f(x)dx. 4. Lx 04-2 x-2 5. If m f(x)