You Answered Correct Answer What is the volume of H in (L) that forms at 463 K and a constant 2.47 atm if 2.92 grams of K reacts with excess water as follows: 2K(s) + 2HO(1) 2KOH + H(g) Gas constant= 0.08206 atm L/(mol K) Enter your number using 2 decimal places and without units. Molecular mass (g/mol): K: 39.10 HO: 18.02 KOH: 56.11 H: 2.018 2.3 0.57 margin of error +/- 5%