You are given the following divide-and-conquer algorithm: Algorithm MinMax(A, 1, r, minval, maxval) if r = 1 - minval A[]; maxval - A[I] else if r -1=1 if A[l] A[r] minval A[]; maxval A[r] - else minval A[r]: maxval A[l] else //r-1>1 a. b. Min Max (A, 1, [(1+r)/2], minval, maxval) Min Max (A, [(1+r)/2]+1, r, minval2, maxval2) if minval2