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You are measuring the viscosity of a power-law fluid and notice that the shear necessary to maintain a strain rate of 476 (1/s) is 234.856
You are measuring the viscosity of a power-law fluid and notice that the shear necessary to maintain a strain rate of 476 (1/s) is 234.856 N/m^2. If we increase the strain by X times, the stress is now 548.499 N/m^2. What is X? Given that the power-law exponent (n) is 1.07 .
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