You are performing an experiment with a very long, uniform, taut nylon rope-such as is being laid out in Fig. 16.10.1. In your experiment, the rope is horizontal when in equilibrium. One end of the rope passes over a massless, frictionless pulley and holds an anchor of mass M. The other end of the rope is connected to a motor that moves perpendicular to the long direction of the rope with simple harmonic motion-see Fig. 16.10.2. The motor's maximum displacement from equilibrium is 5.00 cm, and it moves with a frequency of 27.0 Hz. In so doing, the motor does work on the rope at an average rate if 100 J/s. The mass per unit length of the rope is # = 78.0 g/m. Interactive Figure 16.10.1: This photograph shows a very long nylon rope being laid out. This rope is used to hold ocean buoys that detect tsunamis. (Julie Dermansky/Corbis/ Getty Images) Motor WWWWWW Interactive Figure 16.10.2: A motor produces a sinusoidal wave that travels along a uniform nylon rope under tension. Question 1 Did you consider using the equation for the average power of a sinusoidal wave, Paug = = Now Vmax Pang = /Do? ymax? You are given all these quantities except the wave speed ov. You can then solve for vv. What is the speed v of the wave as it travels along the rope? ! m/sQuestion 2 What is the mass M of the anchor? M = KE Save for Later Attempts: 0 of 5 used Submit Answer Question 3 According to the manufacturer, the rope can withstand a maximum tension magnitude of 24.0 kN. If the rope is placed under this tension and the motor can still provide the same amplitude and frequency, at what average rate does the motor do work on the rope? Paug = i W eTextbook and Media Save for Later Attempts: 0 of 5 used |Submit