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You are playing a card came, and the probability that you will win a game isp = 0.79. If you play the game 1349 times,

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You are playing a card came, and the probability that you will win a game isp = 0.79. If you play the game 1349 times, what is the most likely number of wins? (Round answer to one decimal place.) Let X represent the number of games (out of 1349) that you win. Find the standard deviation for the probability distribution of X. (Round answer to two decimal places.) The range rule of thumb (Empirical Rule) specifies that the minimum usual value for a random variable is uZo and the maximum usual value is u+20. You already found a and 0' for the random variable X. Use the range rule of thumb (Empirical Rule) to find the usual range of Xvalues. Enter answer as an interval using square-brackets and only whole numbers. Written Example of a similar problem Recall that for the binomial distribution: = \"P O' = 'mpq Range Rule of Thumb for Unusual Values-The Range Rule of Thumb (Empirical Rule) for Unusual Values is given by the formulas shown below: 0 Maximum Usual Value = p. | 20' 0 Minimum Usual Value = Ju, 20 Any values outside these ranges are considered unusual. Example: Assume that a procedure yields a binomial distribution with n = 50 trials and the probability of success for one trial is p = 0.12. Step 1: Find the mean:p, = 50- 0.12 = 6 Step 2: Find the standard deviation: 0' = 50 - 0.12 - 0.88 = 2.30 Step 3: Find the range of "usual" values: 0 p, 20' = 6 2(2.30) = 1.4 - p, + 2a = 6 + 2(2.30) = 10.6 Answer: Since the binomial distribution is discrete, the range of usual values should be discrete. Round up the lower bound and round down the upper bound for a result of [2, 10]

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