You are standing on the edge of a cliff overlooking a beach and are again curious about your elevation. You decide the use a ball and a stopwatch to conduct an experiment. You know that the fastest you can throw the ball is v0=25.0m/sv0=25.0m/s. You start the stopwatch as you throw the ball: the ball rises then falls, and passes your level again after t=0.752st=0.752s has elapsed. Sadly, you lose sight of the ball as it falls, and therefore cannot time when the ball hits the ground. Later you head down to the beach and find that the ball landed 112m112m from the base of the cliff. Assuming that the ball did not "bounce" after landing on the sand, how high up was the cliff? Assume that the ball started exactly 1.60m1.60m above the edge of the cliff.

Can someone solve this please? Thanks