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You don't have to give a thorough explanation. But something simple accompanied with the answer works fine. The assignment is due tonight I'd just like

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You don't have to give a thorough explanation. But something simple accompanied with the answer works fine. The assignment is due tonight I'd just like simple clarification. Most likely my teacher will go over the answers so you don't have to give a long explanation but I would like to know what I'm doing as I complete the assignment.

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QUESTION 1 If you draw an M&M candy at random from a bag of the candies, the candy you draw will have one of six colors. The probability of drawing each color depends on the proportion of each color among all candies made. The following table gives the probability that a randomly chosen M&M has each color. (These probabilities came from the M&M's website.) Color Brown Red Yellow Green | Blue |Orange Probability 0.13 0.13 ? 0.16 0.24 0.20 The probability of drawing a yellow candy is 0.14. 0. 16. 1/6 impossible to determine from the information given. QUESTION 2 If you draw an M&M candy at random from a bag of the candies, the candy you draw will have one of six colors. The probability of drawing each color depends on the proportion of each color among all candies made. The following table gives the probability that a randomly chosen M&M has each color. (These probabilities came from the M&M's website.) Color Brown Red Yellow Green Blue Orange Probability 0.13 0.13 ? 0.16 0.24 0.20 The probability that I do not draw a red candy is 0.13. 0.27. -0.87. 5/6. QUESTION 3 A physician observes the number of lesions on subjects who had regularly used tanning salons. Let X be the number of lesions observed. The physician found that X had the following probability distribution. Value of X 0 1 2 3 4 Probability 0.05 0.1 0.25 0.30 0.30 The probability that a randomly chosen subject has at least three lesions is 0.3. 0.4. 0.6. -0.7.QUESTION 4 A physician observes the number of lesions on subjects who had regularly used tanning salons. Let X be the number of lesions observed. The physician found that X had the following probability distribution. Value of X 0 1 2 3 4 Probability 0.05 0.1 0.25 0.30 0.30 P( X > 3) has value 0.3. 0.4. - 0.6. 0 0.7. QUESTION 5 According to the Center for Disease Control and Prevention (CDC), up to 20% of Americans contract the influenza virus each year, and approximately 3% of all births in the United States result in birth defects each year. Consider two babies being born independently of one another. The probability that both babies have birth defects is 0.0009. 0.0400. 0.0606. 0.2000

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