Question
You have a ruler of length 2 and you choose a place to break it using a uniform probability distribution. Let random variable X represent
You have a ruler of length 2 and you choose a place to break it using a uniform probability distribution. Let
random variable X represent the length of the left piece of the ruler. X is distributed uniformly in [0, 2].
You take the left piece of the ruler and once again choose a place to break it using a uniform probability
distribution. Let random variable Y be the length of the left piece from the second break.
a. (3 points) Draw a picture of the region in the X-Y plane for which the joint density of X and Y is
non-zero.
b. (3 points) Compute the joint density function for X and Y . (As always, make sure you write a complete
expression.)
c. (3 points) Compute the marginal probability density for Y , fY (y).
d. (3 points) Compute the conditional probability density of X, conditional on Y = y, fX|Y (x|y). (Make
sure you state the values of y for which this exists.)
Pay extra attention for part d, because it might be very tricky. I am not sure if it is 1/2 or a ln function? Please help me out.
Step by Step Solution
There are 3 Steps involved in it
Step: 1
Get Instant Access to Expert-Tailored Solutions
See step-by-step solutions with expert insights and AI powered tools for academic success
Step: 2
Step: 3
Ace Your Homework with AI
Get the answers you need in no time with our AI-driven, step-by-step assistance
Get Started