You know that at) is a differentiable function and that f(5) = 33 while f'(5) = 612. You also know that: G'(:I:) = [f (517)]3 An equation for the line tangent to the graph of y = G(:c) at the point where m = 5 is: Your answer should be in exact form. So that means no need to try simplifying after solving for y when finding the tangent line.