Question
You know that the fraction of collisions is a ratio of k/A, you can assume that this is directly proportional to the effectiveness of a
You know that the fraction of collisions is a ratio of k/A, you can assume that this is directly proportional to the effectiveness of a reaction. You also know temperature affects rate. Knowing these facts, solve this:
We have a production line that I want to speed up, as time is money. I am considering the option of running the reaction at 90oC instead of 70oC, or I could use a catalyst at 70C. Both options have cost implications with time improvements. By heating to 90C, gas costs would rise by $2,000 per year. Conversely, the catalyst purchase will cost about $20,000 and can be reused for about 3 years.
The activation energy of the reaction at 70oC is 50kJ/mol. The catalyst should drop the activation energy to about 45kJ/mol. What do you recommend, and why? (8 marks)
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