you launch a ball off of a platform of height h with velocity vv at an angle above the horizontal. A wall with a ball-sized hole a height H above the floor, with H>h , is a horizontal distance L=30.0mL away. The difference in height between H and h is one-twelfth of L, and the square of the magnitude of the velocity, v2, is three-halves of the product of gL

Hh=1/12L

v2=32gL

For what values of will the ball make it through the hole in the wall?

Please use simple method.