You may need to use the appropriatetechnologyto answer this question.The following data are from a completely randomized design.

	Treatment
A	B	C
	162	142	125
141	156	123
166	124	138
145	141	141
148	136	150
174	147	133
Sample mean	156	141	135
Sample variance	174.0	115.2	103.6

(a)Compute the sum of squares between treatments.

(b)Compute the mean square between treatments.

(c)Compute the sum of squares due to error.

(d)Compute the mean square due to error. (Round your answer to two decimal places.)

(e)Set up the ANOVA table for this problem. (Round your values for MSE andFto two decimal places, and yourp-valueto four decimal places.)

Source of Variation	Sum of Squares	Degrees of Freedom	Mean Square	F	p-value
Treatments
Error
Total

(f)At the= 0.05 level of significance, test whether the means for the three treatments are equal.State the null and alternative hypotheses.

H₀: _A = _B = _C H_a: _{A B C}

H₀: _{A B C} H_a: _A = _B = _C

H₀: _A = _B = _C H_a: Not all the population means are equal

.H₀: At least two of the population means are equal. H_a: At least two of the population means are different.

H₀: Not all the population means are equal. H_a: _A = _B = _C

Find the value of the test statistic. (Round your answer to two decimal places.) Find thep-value. (Round your answer to four decimal places.)p-value = State your conclusion.

Do not rejectH₀. There is sufficient evidence to conclude that the means for the three treatments are not equal.

Do not rejectH₀. There is not sufficient evidence to conclude that the means for the three treatments are not equal.

RejectH₀. There is sufficient evidence to conclude that the means for the three treatments are not equal.

RejectH₀. There is not sufficient evidence to conclude that the means for the three treatments are not equal.