You now have an indication of what the resultant E field looks like at each of the specific points. The point of observation will now be located at an arbitrary point P=(x, y, 0). b. Field vector at any point P=(x, y, 0): i. On the diagram, sketch the vectors E, and E2 and the resultant vector E (x, y, 0) at the point P=(x, y, 0). ii. For the charges in question 1 - P1 =(-1, 0, 0) and P2=(1, 0, 0), P(x, y, 0) . rewrite equation 21c to find the field at any point P-(x, y, 0) in the x-y (z = 0) plane. Q1 E ( x, y, 0 ) = c. Component of the field in the y - direction at any point P=(x, y, 0): 1 . On the diagram, sketch the resultant vector E(x, y, 0) and the y component - Ey. at the point P=(x, y, 0). ii. Write the equation for the y - component (Ey) (Simplify your P(x, y, 0) . answer from question 1b, above), for the electric field. Ey (x, y, 0 ) = Q 2 d. Component of the field in the x - direction at any point P=(x, y, 0): i . On the diagram, sketch the resultant vector E (x, y, 0) and the x - component - Ex. at the point P=(x, y, 0). ii. Write the equation for the x - component (Ex) (Simplify your answer to question 1b, above), for the electric field P(x, y, 0) . Ex(x, y, 0) = Q1