You prepare two solutions in separate containers (half-cells) and measure the potential between them. One half-cell has cadmium metal, Cd(s), in contact with a solution at pH= 5.44 containing 7.58107MCd2+. The other half-cell has water at pH=0, with hydrogen gas at 1 bar of pressure constantly bubbling through it to maintain equilibrium. The voltmeter says that the half-cell with cadmium is at a potential of 0.581V versus the half-cell with hydrogen. Neglect ionic strength corrections. Based on your measurement, find pe and E for the reduction of Cd2+ to Cd(s)